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x^2+20x+100=156.25
We move all terms to the left:
x^2+20x+100-(156.25)=0
We add all the numbers together, and all the variables
x^2+20x-56.25=0
a = 1; b = 20; c = -56.25;
Δ = b2-4ac
Δ = 202-4·1·(-56.25)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-25}{2*1}=\frac{-45}{2} =-22+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+25}{2*1}=\frac{5}{2} =2+1/2 $
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